Python offers several ways to sort a dictionary based on its keys. Sorting the keys in alphabetical order can be done using the built-in `sorted`

function or by converting the dictionary to a list of tuples, sorting the list, and then constructing a new dictionary from the sorted list.

In this article, we will explore both methods in detail, including code examples for each method.

## Method 1: Using the built-in `sorted`

function

The simplest way to sort a dictionary in alphabetical order by its keys is to use the built-in `sorted`

function. The `sorted`

function takes an iterable object as its input and returns a sorted list of elements.

Here is an example of how to sort a dictionary in alphabetical order by its keys using the `sorted`

function:

```
d = {'dog': 10, 'cat': 5, 'bird': 20}
sorted_keys = sorted(d.keys())
sorted_dict = {}
for key in sorted_keys:
sorted_dict[key] = d[key]
print(sorted_dict)
```

Output:

```
{'bird': 20, 'cat': 5, 'dog': 10}
```

In this example, we first sorted the keys of the dictionary using the `sorted`

function and stored the result in a list named `sorted_keys`

. Then, we created a new dictionary `sorted_dict`

and populated it with the key-value pairs from the original dictionary `d`

, using the sorted keys as the keys in the new dictionary.

## Method 2: Converting the dictionary to a list of tuples

Another way to sort a dictionary in alphabetical order by its keys is to convert the dictionary to a list of tuples, sort the list, and then construct a new dictionary from the sorted list.

Here is an example of how to sort a dictionary in alphabetical order by its keys using this method:

```
d = {'dog': 10, 'cat': 5, 'bird': 20}
sorted_list = sorted(d.items(), key=lambda x: x[0])
sorted_dict = dict(sorted_list)
print(sorted_dict)
```

Output:

```
{'bird': 20, 'cat': 5, 'dog': 10}
```

In this example, we used the `items`

method to convert the dictionary `d`

to a list of tuples. The `items`

method returns a list of key-value pairs as tuples, where each tuple consists of a key and its corresponding value.

Next, we used the `sorted`

function to sort the list of tuples based on the first element of each tuple (the key), using the `key`

parameter. The `key`

parameter is set to a lambda function that returns the first element of the tuple.

Finally, we used the `dict`

constructor to create a new dictionary `sorted_dict`

from the sorted list of tuples.

## Conclusion

In this article, we explored two methods for sorting a dictionary in alphabetical order by its keys in Python. The first method used the built-in `sorted`

function to sort the keys and then construct a new dictionary from the sorted keys. The second method converted the dictionary to a list of tuples, sorted the list, and then constructed a new dictionary from the sorted list.

Both

In addition to sorting a dictionary by its keys, it is also possible to sort a dictionary by its values. This can be done using similar methods as described above, but with a few modifications.

## Method 1: Using the built-in `sorted`

function with `items`

method

To sort a dictionary by its values, you can use the built-in `sorted`

function in combination with the `items`

method. The `items`

method returns a list of key-value pairs as tuples, which can be sorted based on the values.

Here is an example of how to sort a dictionary in ascending order by its values using the `sorted`

function with the `items`

method:

```
d = {'dog': 10, 'cat': 5, 'bird': 20}
sorted_list = sorted(d.items(), key=lambda x: x[1])
sorted_dict = dict(sorted_list)
print(sorted_dict)
```

Output:

```
{'cat': 5, 'dog': 10, 'bird': 20}
```

In this example, the `items`

method returns a list of tuples, where each tuple consists of a key and its corresponding value. The `sorted`

function sorts this list of tuples based on the second element of each tuple (the value), using the `key`

parameter. The `key`

parameter is set to a lambda function that returns the second element of the tuple.

Finally, we used the `dict`

constructor to create a new dictionary `sorted_dict`

from the sorted list of tuples.

To sort the dictionary in descending order by its values, you can use the `reverse`

parameter of the `sorted`

function, as shown in the following example:

```
d = {'dog': 10, 'cat': 5, 'bird': 20}
sorted_list = sorted(d.items(), key=lambda x: x[1], reverse=True)
sorted_dict = dict(sorted_list)
print(sorted_dict)
```

Output:

```
{'bird': 20, 'dog': 10, 'cat': 5}
```

## Method 2: Using the `sorted`

method with a `key`

function

It is also possible to sort a dictionary by its values using the `sorted`

method directly on the dictionary, with a `key`

function that returns the value for each key-value pair.

Here is an example of how to sort a dictionary in ascending order by its values using the `sorted`

method with a `key`

function:

```
d = {'dog': 10, 'cat': 5, 'bird': 20}
sorted_dict = dict(sorted(d.items(), key=lambda x: x[1]))
print(sorted_dict)
```

Output:

```
{'cat': 5, 'dog': 10, 'bird': 20}
```

In this example, the `sorted`

method is applied directly to the dictionary, and the `key`

parameter is set to a lambda function that returns the second element of each tuple (the value). The result of the `sorted`

method is a sorted list of tuples, which is then passed to the `dict`

constructor to create a new dictionary `sorted_dict`

.

To sort the dictionary in descending order

## Popular questions

- What is the most common way to sort a dictionary by its keys in Python?

The most common way to sort a dictionary by its keys in Python is to use the built-in `sorted`

function in combination with the `items`

method. The `items`

method returns a list of key-value pairs as tuples, which can then be sorted based on the keys using the `sorted`

function.

- How can you sort a dictionary in descending order by its keys?

To sort a dictionary in descending order by its keys, you can use the `reverse`

parameter of the `sorted`

function and set it to `True`

. This will sort the list of key-value pairs in reverse order, effectively sorting the dictionary in descending order by its keys.

- What is the difference between using the
`sorted`

function with the`items`

method and using the`sorted`

method directly on the dictionary?

The difference between using the `sorted`

function with the `items`

method and using the `sorted`

method directly on the dictionary is that the `items`

method returns a list of key-value pairs as tuples, which can then be sorted using the `sorted`

function, while the `sorted`

method directly on the dictionary returns a sorted view of the dictionary, which is not a dictionary itself.

- How can you sort a dictionary by its values instead of its keys?

To sort a dictionary by its values instead of its keys, you can use the same methods as described above, but with a few modifications. You can either use the `sorted`

function with the `items`

method and a `key`

function that returns the value for each key-value pair, or use the `sorted`

method directly on the dictionary with a `key`

function that returns the value for each key-value pair.

- Can you provide a code example for sorting a dictionary in descending order by its values?

Yes, here is a code example for sorting a dictionary in descending order by its values:

```
d = {'dog': 10, 'cat': 5, 'bird': 20}
sorted_list = sorted(d.items(), key=lambda x: x[1], reverse=True)
sorted_dict = dict(sorted_list)
print(sorted_dict)
```

Output:

```
{'bird': 20, 'dog': 10, 'cat': 5}
```

In this example, the `sorted`

function is used with the `items`

method to sort the list of key-value pairs based on the values. The `reverse`

parameter is set to `True`

, which sorts the list in reverse order, effectively sorting the dictionary in descending order by its values.

### Tag

Dictionary-Sorting